4.9x^2+24x-300=0

Solution for 4.9x^2+24x-300=0 equation:

4.9x^2+24x-300=0

a = 4.9; b = 24; c = -300;
Δ = b2-4ac
Δ = 242-4·4.9·(-300)
Δ = 6456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6456}=\sqrt{4*1614}=\sqrt{4}*\sqrt{1614}=2\sqrt{1614}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{1614}}{2*4.9}=\frac{-24-2\sqrt{1614}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{1614}}{2*4.9}=\frac{-24+2\sqrt{1614}}{9.8}
$